Matematika soal[tex]( - \frac{3}{4}) + ( - \frac{5}{12} = [/tex][tex]( + \frac{1}{6}) - ( - \frac{1}{2} ) = [/tex][tex]( - \frac{1}{3} ) + ( \frac{1}{6} ) - ( - \frac{2}{3} ) = [/tex][tex]( \frac{4}{9} ) - ( \frac{5}{6} ) = [/tex]#nongasal#pkecara#nocopas​

lisettebergnaumulv – April 05, 2023

soal

[tex]( - \frac{3}{4}) + ( - \frac{5}{12} = [/tex]
[tex]( + \frac{1}{6}) - ( - \frac{1}{2} ) = [/tex]
[tex]( - \frac{1}{3} ) + ( \frac{1}{6} ) - ( - \frac{2}{3} ) = [/tex]
[tex]( \frac{4}{9} ) - ( \frac{5}{6} ) = [/tex]

#nongasal
#pkecara
#nocopas
​

Penjelasan dengan langkah-langkah:

[tex]1). \: ( - \frac{3}{4}) + ( - \frac{5}{12}) = - \frac{9}{12} - \frac{5}{12} = - \frac{14}{12} = - \frac{7}{6} = - 1 \frac{1}{6} [/tex]

[tex]2). \: \: ( + \frac{1}{6}) - ( - \frac{1}{2} ) = ( + \frac{1}{6} ) + ( \frac{3}{6} ) = \frac{4}{6} = \frac{2}{3} [/tex]

[tex]3) \: \: ( - \frac{1}{3} ) + ( \frac{1}{6} ) - ( - \frac{2}{3} ) = - \frac{2}{6} + \frac{1}{6} + \frac{4}{6} = \frac{3}{6} = \frac{1}{2} [/tex]

[tex]4). \: \: ( \frac{4}{9} ) - ( \frac{5}{6} ) = \frac{8}{18} - \frac{15}{18} = - \frac{7}{18} [/tex]

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